[刷题笔记][Python][HackerRank]Built-ins

any()
This expression returns True if any element of the iterable is true.
If the iterable is empty, it will return False.

Code

>>> any([1>0,1==0,1<0])True>>> any([1<0,2<1,3<2])False

all()
This expression returns True if all of the elements of the iterable are true. If the iterable is empty, it will return True.

Code

>>> all(['a'<'b','b'<'c'])True>>> all(['a'<'b','c'<'b'])False

Task

You are given a space separated list of integers. If all the integers are positive, then you need to check if any integer is a palindromic integer.

Input Format

The first line contains an integer . is the total number of integers in the list.
The second line contains the space separated list of integers.

Constraints

Output Format

Print True if all the conditions of the problem statement are satisfied. Otherwise, print False.

Sample Input

512 9 61 5 14 

Sample Output

True

Explanation

Condition 1: All the integers in the list are positive.
Condition 2: 5 is a palindromic integer.

Hence, the output is True.

Can you solve this challenge in 3 lines of code or less?
There is no penalty for solutions that are correct but have more than 3 lines.

solve

s, n = int(input()), list(map(int, input().split())) #读取输入print(all(val > 0 for val in n) and any(str(num) == str(num)[::-1] for num in n)) #利用python list[::-1]反转的方式check，并使用any()其中只要有一组满足就会输出True